I often see a log where I want to print sequential columns in the log for a purpose.
Problem
How to print all columns from the nth to the last?
Solution
For example, you have a test.txt file that contains the following:
No Name Address
1 Richard Apt. 344 86094 Swaniawski Drive, East Suzetteshire, MT 51323-2013
2 Alex 4522 Rosenbaum Island, Lake Suzan, IL 68193
3 Bryan Apt. 907 703 Douglas Run, West Brainburgh, MT 70080-8990

Usually, to display the complete Address column, I will run the command below:
awk '{print $3,$4,$5,$6,$7,$8,$9,$10,$11,$12}' test.txt

However, I think this method is less effective because if the address is more than 12 columns, then I have to write more than 12 items, and it is very tiring. After searching on the internet, there are 2 methods you can use:
1. Using the awk command
From the test.txt file, you just want to print the entire column except columns 1 and 2, then you can use the command below:
awk '{$1=$2=""; print $0}' test.txt
The result will be as shown in the image below:

2. Using the cut command
In addition to using awk, you can also use the cut command to display the same by using the command below:
cut -d' ' -f3- test.txt
And the result will be as shown in the image below when you run the command above:

cut -d" " -f7- test.txt
Note
There are still several methods to print columns that run from the nth to the last column, but I think those two methods will suffice.
References
testingbot.com
stackoverflow.com

